Yes it will work in this specific case. What I meant was that Radix sort isn't 
always applicable in general to achieve linear time sorting. Its complexity 
isn't exactly O(N) rather O(d*N) where d is the number of bytes each of our 
item consumes. So if the elements in array aren't from a finite range, that 
would be an issue. 

Correct me if I am wrong. 

--
Shuaib
http://twitter.com/ShuaibKhan
http://www.bytehood.com/

On 16-Aug-2011, at 11:05 AM, Dave <[email protected]> wrote:

> @Shuaib: It will work in all cases. If you don't think so, give a
> counterexample.
> 
> Dave
> 
> On Aug 16, 12:50 am, Shuaib <[email protected]> wrote:
>> That will work but not in all cases as radix sort isn't a generalized 
>> sorting algorithm, is it? :)
>> 
>> --
>> Shuaibhttp://twitter.com/ShuaibKhanhttp://www.bytehood.com/
>> 
>> On 16-Aug-2011, at 10:10 AM, Dave <[email protected]> wrote:
>> 
>> 
>> 
>>> @Shuaib: You could sort the numbers in O(n) with a radix sort, and
>>> then finding the min is easy. Mind you, the radix sort might be slower
>>> than an O(n log n) sort, but still it satisfies the O(n) constraint.
>> 
>>> Dave
>> 
>>> On Aug 15, 8:41 pm, Shuaib <[email protected]> wrote:
>>>> That won't work. And I don't think an O(n) solution is possible.
>> 
>>>> --
>>>> Shuaibhttp://twitter.com/ShuaibKhanhttp://www.bytehood.com/
>> 
>>>> On 16-Aug-2011, at 6:25 AM, sukran dhawan <[email protected]> wrote:
>> 
>>>>> find the minimum of two numbers in a loop o(n) and subtract the two
>> 
>>>>> On Tue, Aug 16, 2011 at 6:13 AM, Brijesh Upadhyay 
>>>>> <[email protected]> wrote:
>>>>> Algorithm to find the two numbers whose difference is minimum among the 
>>>>> set of numbers. For example the sequence is 5, 13, 7, 0, 10, 20, 1, 15, 
>>>>> 4, 19 The algorithm should return min diff = 20-19 = 1. Constraint - Time 
>>>>> Complexity O(N)
>> 
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