I think it should be 2^n -1 Explanation We can visualize it as n balls are placed and we have to place some dividers (max=n) in betweek to divide them into groups.
If we choose no divider its nC0 , but we dont have to include it With 1 divider its nC1 and so on.. So the total no. of ways will be (nC0+nC1+nC2..........nCn)-nC0= 2^n-1 Regards, Puneet On Wed, Aug 17, 2011 at 4:05 PM, Rohit Srivastava <[email protected]>wrote: > +1 to nitin > > > On Wed, Aug 17, 2011 at 2:48 PM, Vijay Kansal <[email protected]>wrote: > >> my bad 2^(n-1)... >> >> On Aug 17, 2:17 pm, Vijay Kansal <[email protected]> wrote: >> > @nitin it must be 2^n i think >> > >> > On Aug 17, 3:48 am, Bharat Kul Ratan <[email protected]> wrote: >> > >> > >> > >> > >> > >> > >> > >> > > It might be useful: >> http://www.artofproblemsolving.com/Wiki/index.php/Partition_%28combin... >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> >> > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- ----------------------------------------------------------------------- Puneet Goyal Student of B. Tech. III Year (Software Engineering) Delhi Technological University, Delhi ----------------------------------------------------------------------- -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
