@Arjoo kumar value of loops will vary acc to sum is odd or even
loops = sum/2 (sum even)
=(sum/2) + 1 (sum odd)
Ashima
M.Sc.(Tech)Information Systems
4th year
BITS Pilani
Rajasthan




On Fri, Aug 19, 2011 at 11:10 AM, Sanjay Rajpal <[email protected]>wrote:

> Plz make one point clear can we use extra space or not ?
>
> because complexity will vary depending upon the approach.
>
> *Regards
>
> Sanju
>
> Happy to Help :)*
>
>
>
>
> On Fri, Aug 19, 2011 at 11:04 AM, arjoo kumar <[email protected]> wrote:
>
>> find
>> 1....length1 (arr1)
>> 2....length 2(arr2)
>> 3....sum = length1 +length 2
>> 4....loops = sum /2
>> 5... set two pointer (say ptr1 & ptr2) on arr[0]& arr2[0]
>> 6.... start loop for i =1 to loops
>>           if (*ptr1 <= *ptr2 )
>>                ptr1++
>>           else
>>                ptr2++
>>
>> please manage it & remaining part send after some time
>>
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