what are you trying to say?...can you please explain?

On Sun, Aug 21, 2011 at 1:35 PM, JAIDEV YADAV <[email protected]> wrote:

> try to use X b = a ; b.fun() ;
>
> On Sun, Aug 21, 2011 at 1:33 PM, Abhishek Yadav <
> [email protected]> wrote:
>
>> ok...may be i forgot , can you please tell me correct code for the copy
>> constructor..?
>>
>>
>> On Sun, Aug 21, 2011 at 1:31 PM, JAIDEV YADAV <[email protected]> wrote:
>>
>>> dude u haven't used copy constructor properly .. check it out again ...
>>> you are not copying actually ... thats it ...
>>>
>>> On Sun, Aug 21, 2011 at 12:53 PM, Abhishek Yadav <
>>> [email protected]> wrote:
>>>
>>>> Check this code: the thing i couldn't understand is when the object is
>>>> being returned neither the copy constructor is being called nor the
>>>>  assignment operator overload is called....then how the object is being
>>>> copied into b. i don't think default copy constructor should be called if i
>>>> have made our own copy constructor....???
>>>> #include<iostream>
>>>> using namespace std;
>>>> #include<conio.h>
>>>>
>>>> class X
>>>> {
>>>>       public:
>>>>   int num;
>>>>     X(int a)
>>>>     {
>>>> num=a;
>>>>              cout<<"\n constructor";
>>>>     }
>>>>
>>>>     X(const X& t)
>>>>  {
>>>> this->num=t.num;
>>>> cout<<"\nCopy ";
>>>>  }
>>>>
>>>> X operator=(const X& t)
>>>> {
>>>>  this->num =t.num;
>>>> cout<<"\n Assigment   ";
>>>> return t;
>>>>  }
>>>>
>>>>     X fun()
>>>>     {
>>>>            cout<<"\nin fun";
>>>>            return X(7);
>>>>      }
>>>>
>>>> ~X()
>>>> {
>>>> cout<<"\ndestruct ";
>>>>  }
>>>>
>>>> };
>>>>
>>>> int main()
>>>> {
>>>> {
>>>>     X a(1);
>>>>    X b=a.fun();
>>>>    cout<<"\n\n"<<b.num;
>>>> }
>>>> getch();
>>>> }
>>>>
>>>>
>>>> On Sun, Aug 21, 2011 at 12:33 PM, Abhishek Yadav <
>>>> [email protected]> wrote:
>>>>
>>>>> The code is correct..return X will make a temporary object and for that
>>>>> a constructor and corresponding destructor will be called and that  object
>>>>> is returned.
>>>>>
>>>>> On Sun, Aug 21, 2011 at 12:24 PM, Puneet Chawla <
>>>>> [email protected]> wrote:
>>>>>
>>>>>> It will show error
>>>>>>
>>>>>> On Sun, Aug 21, 2011 at 12:21 PM, Sanjay Rajpal <[email protected]>wrote:
>>>>>>
>>>>>>> I think it will not be an error.
>>>>>>>
>>>>>>> This is because X() will create a temporary object, and when the
>>>>>>> object is returned in the function calling it, then default copy
>>>>>>> constructor will do bitwise copy of data members in the calling
>>>>>>> function.
>>>>>>>
>>>>>>> Correct me if m wrong.
>>>>>>>
>>>>>>> On 8/20/11, sachin sabbarwal <[email protected]> wrote:
>>>>>>> > class X()
>>>>>>> > {
>>>>>>> >
>>>>>>> > X()
>>>>>>> > {
>>>>>>> > }
>>>>>>> >
>>>>>>> >
>>>>>>> >
>>>>>>> > X fun()
>>>>>>> > {
>>>>>>> > return X();      //error or what?? because constructor never
>>>>>>> returns
>>>>>>> > anything so what this return statement will receive after executing
>>>>>>> x() and
>>>>>>> > what it will return??
>>>>>>> > }
>>>>>>> >
>>>>>>> >
>>>>>>> > };
>>>>>>> >
>>>>>>> > --
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>>>>>>> >
>>>>>>> >
>>>>>>>
>>>>>>>
>>>>>>> --
>>>>>>> Sanju
>>>>>>> :)
>>>>>>>
>>>>>>> --
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>>>>>>>
>>>>>>>
>>>>>>
>>>>>>
>>>>>> --
>>>>>> With regards
>>>>>>   ............
>>>>>> Puneet Chawla
>>>>>> Computer Engineering Student
>>>>>> NIT Kurukshetra
>>>>>>
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>>>>>>
>>>>>
>>>>>
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>>>>
>>>
>>>
>>>
>>> --
>>> JaiDev Yadav
>>> (National Yoga Champion)
>>> Computer Engg. Dept.
>>> National Institute of Technology
>>> Kurukshetra,Haryana
>>>
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>>
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>
>
>
> --
> JaiDev Yadav
> (National Yoga Champion)
> Computer Engg. Dept.
> National Institute of Technology
> Kurukshetra,Haryana
>
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