Hi Nitin,

thanks that makes sense. I will try that out.

I have another question. Is there a  really fast way of converting a
hexadecimal string say "02F9A" to its decimal representation in C++?

thanks,
Sarvesh

thanks,
Sarvesh

On Sun, Aug 21, 2011 at 3:41 PM, Nitin Nizhawan <[email protected]>wrote:

> int num = 0;
> for(int i=0;i<A.size();i++){
>    num=num||(A[i]<<3*i);
> }
> printf("%d",num);
>
> I think this will do. Given the number is with in the range of integer.
>
>
> On Sun, Aug 21, 2011 at 3:40 PM, Nitin Nizhawan 
> <[email protected]>wrote:
>
>> int num = 0;
>> for(int i=0;i<A.size();i++){
>>    num=num||(A[i]<3*i);
>> }
>> printf("%d",num);
>>
>> I think this will do.
>>
>>
>> On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran <
>> [email protected]> wrote:
>>
>>> Hi,
>>>
>>> I have a vector<int> A or an array (for C guys) that contains the octal
>>> representation of a number.
>>>
>>> So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
>>>
>>> i.e no number in the array can be >= 8.
>>>
>>> Now given this array, I need to convert it its decimal representation.
>>>
>>> The naive way to do it would be to scan array from left to right, take
>>> each digit, multiply by 8 pow (x) where x is from 0 to ...n and compute sum.
>>>
>>> i.e something like:
>>>
>>> int oct = 1;
>>> int num = 0;
>>>
>>>  for(<array length>){
>>>         num+= oct * A[i];
>>>         oct = oct * 8;
>>>     }
>>>
>>> is there a faster way to do this? maybe using some STL container or 
>>> algorithm. ?
>>>
>>> thanks,
>>> sarvesh
>>>
>>>
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>>
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