:P.. no comments when i saw On Sun, Aug 21, 2011 at 4:07 PM, sagar pareek <[email protected]> wrote:
> @prakash > before posting u should check what others already posted :D :D > > On Sun, Aug 21, 2011 at 4:03 PM, Prakash D <[email protected]> wrote: > >> FUNC2(8) >> >> ==> 8==0? 1: 8 * FUNC1(8-1) >> ==> 8==0? 1: 8*( 8-1* 8-1-1) >> >> ==> 8 * (8-8-2) >> ==> -16 >> >> but why 16?? >> >> On Sat, Aug 20, 2011 at 7:02 PM, SuDhir mIsHra <[email protected] >> > wrote: >> >>> #include<stdio.h> >>> #define FUNC1(i) (i*(i-1)) >>> #define FUNC2(i) (i==0?1:i*FUNC1(i-1)) >>> main() >>> { >>> int i=8; >>> >>> >>> printf("\n%d",FUNC2(i)); >>> } >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "Algorithm Geeks" group. >>> To post to this group, send email to [email protected]. >>> To unsubscribe from this group, send email to >>> [email protected]. >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > **Regards > SAGAR PAREEK > COMPUTER SCIENCE AND ENGINEERING > NIT ALLAHABAD > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
