On Aug 24, 6:00 pm, Sanjay Rajpal <[email protected]> wrote:
> after first scanf, place a call to fflush(stdin).
>
> you will get the result.
>
> Sanju
> :)
>
>
>

Flushing the input stream is undefined.

>
>
>
>
> On Wed, Aug 24, 2011 at 5:58 AM, Mehnaaz <[email protected]> wrote:
> > #include <stdio.h>
> > #define max 30
> > int no_p;
> > int main() {
>
> >        char p[no_p][max];
> >        char x;
> >        int i=0;
> >        printf("enter the no of productions..\n");
> >                scanf("%d", &no_p);
> >                printf("you have entered :%d\n", no_p);
> >                printf("Variable who's FOLLOW you want\n");
> >                scanf("%c", &x);
> >                printf("you have entered :%c",X);
> >                printf("\n");
> >                for( i =0 ; i< no_p ; i++){
> >                printf("enter the production # %d",i+1);
> >                scanf("%s",p[i]);
> >                }
> >                //follow(p,x);
> > return 0;
> > }
>
> > the output i am getting goes like this
> > ......................................
> > enter the no of productions..
> > 3
> > you have entered :3
> > Variable who's FOLLOW you want
> > you have entered :
>
> > enter the production # 1
> > ...........................................
> > at the line 4 of the output its supposed to wait for my scanf() entry
> > value right??..but it executes the printf after that giving "you have
> > entered"
>
> > i'm using gcc to compile this
>
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