int add(int a,int b)
{
int sum=a^b;
int carry=a&b;
while(carry!=0)
{
carry<<=1;
a=sum;
b=carry;
sum=a^b;
carry=a&b;
}
return sum;
}
On Sat, Aug 27, 2011 at 12:28 PM, Mohit kumar lal
<[email protected]>wrote:
> int add(int a, int b)
> {
> if (!a)
> return b;
> else
> return add((a & b) >> 1, a ^ b);
>
> }
>
> On Sun, Aug 28, 2011 at 12:54 AM, sagar pareek <[email protected]>wrote:
>
>> yeah one option is half adder with "xor" and "and" operators
>>
>> one more solution
>>
>> http://www.ideone.com/B07bn
>>
>>
>> On Sun, Aug 28, 2011 at 12:41 AM, Gaurav Menghani <
>> [email protected]> wrote:
>>
>>> I guess you mean without using any 'arithmetic operator'. If yes, it
>>> can be done with XOR and AND operators.
>>>
>>> Not sure how it can be done otherwise, without using any kind of
>>> operators AT ALL.
>>>
>>> On Sun, Aug 28, 2011 at 12:37 AM, Brijesh <[email protected]>
>>> wrote:
>>> > How to add two nos without using any operator...?
>>> >
>>> > --
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>>>
>>>
>>>
>>> --
>>> Gaurav Menghani
>>>
>>> --
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>>>
>>
>>
>> --
>> **Regards
>> SAGAR PAREEK
>> COMPUTER SCIENCE AND ENGINEERING
>> NIT ALLAHABAD
>>
>> --
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>>
>
>
>
> --
> Mohit kumar lal
> rit2009014
> IIIT ALLAHABAD
> contact@9454681805
> [email protected]
> [email protected]
> [email protected]
> http://profile.iiita.ac.in/rit2009014
>
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