yes, u are correct!! thanks
On Sun, Aug 28, 2011 at 7:39 PM, Kamakshii Aggarwal
<[email protected]>wrote:
> @prashant:
> if u remove else from this line
> else if(lenght+2 <= N)
> { Printf (" -->two steps -->") call printPath (length+2) }
> i think then the code will work properly.
> correct me if i am wrong
> On Sun, Aug 28, 2011 at 7:01 PM, prashant thorat <[email protected]
> > wrote:
>
>> sorry, pls ignore above code ..a bit modifie code
>>
>> I'm passing length = 0
>>
>>
>> printPath (int length)
>> {
>> if(lenght == N) return;
>> else
>> {
>> if(lenght+1 <= N)
>> { Printf (" -->one step -->") call printPath (length+1) }
>>
>> else if(lenght+2 <= N)
>> { Printf (" -->two steps -->") call printPath (length+2) }
>>
>> else
>> return;
>> }
>> On Sun, Aug 28, 2011 at 6:54 PM, Kamakshii Aggarwal <
>> [email protected]> wrote:
>>
>>> what is the initial value of length that u r passing??
>>>
>>> On Sun, Aug 28, 2011 at 6:47 PM, prashant thorat <
>>> [email protected]> wrote:
>>>
>>>> Hi, you can do this by recursion ,
>>>>
>>>> printPath (int length)
>>>> {
>>>> if(lenght == N) return;
>>>> else
>>>> {
>>>> if(lenght+1 >= N) { Printf (" -->one step -->") call printPath
>>>> (length+1) }
>>>> else if(lenght+2 >= N) { Printf (" -->two steps -->") call printPath
>>>> (length+2) }
>>>> else
>>>> return;
>>>>
>>>> }
>>>> }
>>>> On Sun, Aug 28, 2011 at 5:42 PM, himanshu kansal <
>>>> [email protected]> wrote:
>>>>
>>>>> you have a path of N steps....
>>>>> at every step, you can take onl;y 1 step or 2 steps.....
>>>>>
>>>>> how to print all the possible paths that you can take......
>>>>>
>>>>> PS: please dont give the exact code.....your approaches will be
>>>>> appreciated....:)
>>>>>
>>>>> --
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>>>>>
>>>>>
>>>>
>>>>
>>>> --
>>>> Yours affectionately,
>>>> Prashant Thorat
>>>> Computer Science and Engg. Dept,
>>>> NIT Durgapur.
>>>>
>>>> --
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>>>
>>>
>>>
>>> --
>>> Regards,
>>> Kamakshi
>>> [email protected]
>>>
>>> --
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>>>
>>
>>
>>
>> --
>> Yours affectionately,
>> Prashant Thorat
>> Computer Science and Engg. Dept,
>> NIT Durgapur.
>>
>> --
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>>
>
>
>
> --
> Regards,
> Kamakshi
> [email protected]
>
> --
> You received this message because you are subscribed to the Google Groups
> "Algorithm Geeks" group.
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> To unsubscribe from this group, send email to
> [email protected].
> For more options, visit this group at
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>
--
Yours affectionately,
Prashant Thorat
Computer Science and Engg. Dept,
NIT Durgapur.
--
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