void rev_str(int i)
{
if(i==((length/2)))
return ;
rev_str(i+1);
SWAP(str[i],str[length-1-i],t);
}
passing 0 as parameter...
On Mon, Aug 29, 2011 at 5:43 PM, mani walia <[email protected]> wrote:
> aa chak code
>
>
> #include<conio.h>
>
> #include<stdio.h>
>
> void rev(char*);
>
> int main()
> {
>
>
>
> rev("hello sexy how are you");
>
> getch();
> }
> void rev(char *t)
> {
>
> if(*t)
> {
>
> rev(t+1);
> }
> printf("%c",*t);
>
> }
>
>
> khush reh... lol
>
>
> On Mon, Aug 29, 2011 at 5:38 PM, saurabh singh <[email protected]>wrote:
>
>> http://www.ideone.com/kSaff
>>
>>
>> On Mon, Aug 29, 2011 at 4:17 PM, rohit agarwal <[email protected]
>> > wrote:
>>
>>> Print the last character of a string and call the function recursively
>>> with remaining string (of length (n-1))
>>>
>>>
>>> --
>>> * Thanks and Regards*
>>> ┌─────────────────────────┐
>>> Rohit Agarwal
>>> Final Year
>>> B.Tech (Information Technology)
>>> NIT Durgapur <http://www.nitdgp.ac.in>
>>> └─────────────────────────┘
>>>
>>>
>>>
>>>
>>> --
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>>>
>>
>>
>>
>> --
>> Saurabh Singh
>> B.Tech (Computer Science)
>> MNNIT ALLAHABAD
>>
>>
>>
>> --
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>
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--
*Dheeraj Sharma*
Comp Engg.
NIT Kurukshetra
+91 8950264227
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