If you draw the nxn grid and assign a value to each diagonal: (For n = 5)
----------b | 12345 | 2345 | 345 | 45 | 5 a You want the result to be the orthogonal distance from the diagonal. That is what the formula computes. Don On Aug 29, 11:28 am, Piyush Grover <[email protected]> wrote: > I understand what you are doing in the loop but return statement is not > clear to me. Can you explain. > > On Mon, Aug 29, 2011 at 9:48 PM, Don <[email protected]> wrote: > > int custRand(int n) > > { > > int a,b; > > do > > { > > a = rand(n); > > b = rand(n); > > } while(a < b); > > return n - a + b; > > } > > > On Aug 29, 10:48 am, Piyush Grover <[email protected]> wrote: > > > Given a function rand(n) which returns a random value between 1...n > > assuming > > > equal probability. > > > Write a function CustRand(n) using rand(n) which returns a value between > > > 1...n such that > > > the probability of occurrence of each number is proportional to its > > value. > > > > I have a solution but wondering if I can get better than this or some > > other > > > approaches: > > > > CustRand(n){ > > > > sum = n*(n+1)/2; > > > > a = rand(sum); > > > for(i = 1; i <= n; i++){ > > > h = i*(i+1)/2; > > > l = i*(i-1)/2; > > > if(a <= h && a > l) > > > return i; > > > } > > > > } > > > -- > > You received this message because you are subscribed to the Google Groups > > "Algorithm Geeks" group. > > To post to this group, send email to [email protected]. > > To unsubscribe from this group, send email to > > [email protected]. > > For more options, visit this group at > >http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
