yes     .964 easy hai yaar

On Mon, Aug 29, 2011 at 5:47 AM, vishwa <[email protected]> wrote:

> if first is hit then the probability will be 0.7....he missed 1st chance ,,
> probability with which he missed is 0.3 ... same way he will try 2nd
> chance.. hit chance is 0.6.. but he missed first already.. so total
> probabilty of hit is 0.3*0.6... its the same way for all.
>
>
>
>
> On Mon, Aug 29, 2011 at 6:06 PM, Naman Mahor <[email protected]>wrote:
>
>> abhishek's answer.
>> plz  clear my confusion
>> that i hv mentioned above.
>>
>> On Mon, Aug 29, 2011 at 6:04 PM, vishwa <[email protected]> wrote:
>>
>>> @naman: whose answer man
>>>
>>>
>>> On Mon, Aug 29, 2011 at 5:56 PM, Naman Mahor <[email protected]>wrote:
>>>
>>>> ur answer is correct but i hv a confusion that all four shots fire at a
>>>> time so there may be probability that all shots hits the craft. but ur
>>>> assuming that first hit + first not hit * second hit+......
>>>> plz clear my confustion
>>>>
>>>> On Mon, Aug 29, 2011 at 5:49 PM, Abhishek Yadav <
>>>> [email protected]> wrote:
>>>>
>>>>> i guess it would be ....   0.7 + 0.3*0.6 + 0.3*0.4*0.5
>>>>> + 0.3*0.4*0.5*0.4 =.964.....correct me if i am wrong.??
>>>>>
>>>>> On Mon, Aug 29, 2011 at 5:34 PM, Naman Mahor <[email protected]>wrote:
>>>>>
>>>>>> An anti aircraft gun can fire four shots at a time. If the
>>>>>> probabilities of the first, second, third and the last shot hitting the
>>>>>> enemy aircraft are 0.7, 0.6, 0.5 and 0.4, what is the probability that 
>>>>>> four
>>>>>> shots aimed at an enemy aircraft will bring the aircraft down?
>>>>>>
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