@AnikKumar: Most people normally wouldn't have difficulty with
probabilities on the real numbers. E.g., there is a target with two
regions, the bullseye with radius 1 and a concentric region with
radius 2. What is the probability of a randomly-thrown dart hitting
the bullseye, given that it hits the target? Most people would say
that since the area of the bullseye is 1/4 the area of the target, the
probability is 1/4. Wouldn't you say that, too?

Dave

On Aug 29, 11:15 pm, AnilKumar B <[email protected]> wrote:
> Agree with Don.
>
> But what if we want to find probability of on real line?
>
> How we can consider R as sample space?
>
> Is that Sample space should be COUNTABLE and FINITE?
>
> *By the quadratic formula, a is 2.08712 or 47.9128.
> The range is 45.8256.
> A falls in the range of 1..100 or 99. So the probability is 47.9128/99*
> *
> *
> *Here you are considering Sample space as length of the interval, right? but
> i think it should be cardinal({x/x belongs to Q and x belongs to [1,100]}).*
>
> On Fri, Aug 26, 2011 at 2:04 AM, Aditya Virmani 
> <[email protected]>wrote:
>
>
>
> > +1 Don... nthin is specified fr the nature of numbers if thy can be
> > rational or thy hav to be only natural/integral numbers...
>
> > On Wed, Aug 24, 2011 at 9:33 PM, Don <[email protected]> wrote:
>
> >> First find the endpoints of the region where the condition is met:
>
> >> a + 100/a = 50
> >> a^2 - 50a + 100 = 0
> >> By the quadratic formula, a is 2.08712 or 47.9128.
> >> The range is 45.8256.
> >> A falls in the range of 1..100 or 99. So the probability is 47.9128/99
> >> = 0.48397
>
> >> Don
>
> >> On Aug 23, 11:56 am, ramya reddy <[email protected]> wrote:
> >> > Let 'a' be  a number between 1 and 100. what is the probability of
> >> choosing
> >> > 'a' such that a+ (100/a) <50
>
> >> > --
> >> > Regards
> >> > Ramya
> >> > *
> >> > *
> >> > *Try to learn something about everything and everything about something*
>
> >> --
> >> You received this message because you are subscribed to the Google Groups
> >> "Algorithm Geeks" group.
> >> To post to this group, send email to [email protected].
> >> To unsubscribe from this group, send email to
> >> [email protected].
> >> For more options, visit this group at
> >>http://groups.google.com/group/algogeeks?hl=en.
>
> >  --
> > You received this message because you are subscribed to the Google Groups
> > "Algorithm Geeks" group.
> > To post to this group, send email to [email protected].
> > To unsubscribe from this group, send email to
> > [email protected].
> > For more options, visit this group at
> >http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text -
>
> - Show quoted text -

-- 
You received this message because you are subscribed to the Google Groups 
"Algorithm Geeks" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to 
[email protected].
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.

Reply via email to