I check out the code:
#include<stdio.h>
main()
{
static int i=10;
while(i>0)
{
--i;
main();
printf("%d",i);
}
}
if you run this you get 0000000000 as output
but if you run this
#include<stdio.h>
main()
{
static int i=10;
while(i>0)
{
--i;
main();
printf("%d",i);
}
}
You get 0-1-2-3-4-5-6-7-8 as output.
Whats the difference in these?
On Wed, Aug 31, 2011 at 7:52 PM, aditi garg <[email protected]>wrote:
> @abhishek: y till -8?
>
>
> On Wed, Aug 31, 2011 at 7:50 PM, vishal jain <[email protected]>wrote:
>
>> I executed on linux machine..
>>
>> I am gettign output
>>
>> 0-1-2-3-4-5-6-7-8 :(
>>
>> for code
>> int main()
>>
>> {
>> static int i=10;
>> while(--i>0)
>> {
>> main();
>> printf("%d",i);
>> }
>> return 0;
>> }
>>
>>
>> On Wed, Aug 31, 2011 at 7:48 PM, Abhishek Mallick <
>> [email protected]> wrote:
>>
>>> The recursion will run 10 times printing nothing. Then ones it returns
>>> on the 10th one. It will start printing from 0 to -8 (As i is static).
>>>
>>> On Aug 31, 6:33 pm, ravi maggon <[email protected]> wrote:
>>> > Ans would be 0000000000, keep in mind that i is static variable.
>>> >
>>> > On Wed, Aug 31, 2011 at 6:59 PM, rohit <[email protected]> wrote:
>>> > > 123456789
>>> >
>>> > > --
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>>> >
>>> > --
>>> >
>>> > Regards
>>> > Ravi Maggon
>>> > Final Year, B.E. CSE
>>> > Thapar University
>>>
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>
>
>
> --
> Aditi Garg
> Undergraduate Student
> Electronics & Communication Divison
> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi
>
>
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--
Regards
Ravi Maggon
Final Year, B.E. CSE
Thapar University
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