I think it is simply printing the subsets.Let Y1 be a subset,then Y-Y1 will
be Y2,which will give u all the partitions...

On Fri, Sep 2, 2011 at 7:04 PM, kranthi raj <[email protected]> wrote:

> I have a list / array Y (with n elements in it), and write an algorithm
> which gives all valid bipartitions (Y1 ,Y2) of Y.
>
> --
>    Sincerely,
>     Kranthi Raj A
>     2nd Mtech
>     Dept Of Computer Science ,
>     Indian Institute of Technology, Madras
>    #9884989577
>
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-- 
*Regards,*
*Piyush Kapoor,*
*2nd year,CSE
IT-BHU*

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