yes n/4 swaps are required. +1 aditya kumar

On Sun, Sep 4, 2011 at 6:32 PM, aditya kumar
<[email protected]>wrote:

> swap n/2-1 with n/2+1 , and then n/2-3 with n/2+3 till we reach n-1 .
> so we need n/4 swaps .
>
>
> On Sun, Sep 4, 2011 at 5:28 PM, Anup Ghatage <[email protected]> wrote:
>
>> That's interesting.
>>
>> when n = 3
>>
>> We have been given this :F F F | E E E
>>
>> Swap the middle element and it becomes: F E F | E F E
>>
>> Which is what you want, but when n = 5
>>
>> F F F F F | E E E E E
>>
>> And you swap the middle element it becomes: F F E F F | E E F E E
>>
>> So the same startegy doesn't apply.
>>
>> But if you do with from the center for every alternate element, it works
>>
>> for n = 3
>>
>> F F F | E E E > F F E | F E E > E F E | E F E
>>
>> It also works for n = 5 etc. So, It is a more uniform solution if you may.
>>
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-- 
Thx,
--Gopi

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