the answers are poy[i] = 1 pot[i] = 2 pot[i] = 8 pot[i] = 64 On Mon, Sep 5, 2011 at 7:55 PM, sukran dhawan <[email protected]>wrote:
> well > > > #define SIZEOF(arr) (sizeof(arr)/sizeof(arr[0])) gives the number of > elements ie sizeof whole array /sizeof first element > > second macro > > #expr - prints variable name > > and if value is preceded is 0 it means it s in octal formt.it is printed > in decimal format by conversion > hope i am clear > > > > On Mon, Sep 5, 2011 at 7:48 PM, Mohit Goel <[email protected]>wrote: > >> 1) #include <stdio.h> >> #include <stdlib.h> >> >> #define SIZEOF(arr) (sizeof(arr)/sizeof(arr[0])) >> >> #define PrintInt(expr) printf("%s:%d\n",#expr,(expr)) >> int main () >> { >> /* The powers of 10 */ >> int pot[] = { >> 0001,0010,0100,1000 >> >> }; >> int i; >> >> for(i=0;i<SIZEOF(pot);i++) >> PrintInt(pot[i]); >> return 0; >> } >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
