1) #include <stdio.h>
#define PrintInt(expr) printf("%s : %d\n",#expr,(expr))
int max(int x, int y)
{
(x > y) ? return x : return y;
}
int main ()
{
int a = 10, b = 20;
PrintInt(a);
PrintInt(b);
PrintInt(max(a,b));
}
2 #include <stdio.h>
void foo(const char **p) { }
int main (int argc, char **argv)
{
foo(argv);
return 0;
}
i think sending a normal pointer to a function
requiring const pointer does not give any warning..but it still giving an
error....
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