i think the output is return type of main(); On Sep 7, 9:19 am, rahul vatsa <[email protected]> wrote: > the expression to sizeof is analyzed @compile time to determine its type. > so, when u do sizeof(main()) in main( ), it doesn't call main again, it just > gets the type of the function. > if you declare main as void main( ) o/p will be 1 > if its int main( ) o/p 4 > > if you just write main in an expression, usually it implicitly converts to > corresponding function pointer, but in case of being argument of sizeof, > compiler doesn't do this conversion. so > sizeof(main) will also be 1 or 4 depending on the prototype of main. > > > > > > > > On Tue, Sep 6, 2011 at 11:25 PM, rahul vatsa <[email protected]> wrote: > > sizeof(void) -> 1 > > > void is a datatype, though u cant create obj of void type, then also it hs > > to hs a size, so it hs been given the minimal sz i.e 1. > > > On Tue, Sep 6, 2011 at 3:13 PM, Kunal Patil <[email protected]> wrote: > > >> @siddharam suresh: sizeof(void) is an prohibited operation. So your code > >> would result in compile time error. > > >> On Tue, Sep 6, 2011 at 11:47 PM, siddharam suresh < > >> [email protected]> wrote: > > >>> my guess, > >>> sizeof() takes only the declaration properties not the definition > >>> properties(that means it wont call the function) > > >>> *#include<stdio.h>* > >>> *void c(); * > >>> *int main()* > >>> *{* > >>> *printf("%d",sizeof(c()));* > >>> *}* > >>> *void c()* > >>> *{* > >>> *printf("c"); * > >>> *}* > >>> *o/p:* > >>> *1* > > >>> Thank you, > >>> Sid. > > >>> On Tue, Sep 6, 2011 at 11:41 PM, siddharam suresh < > >>> [email protected]> wrote: > > >>>> its size of return type, but why the above program not showing > >>>> segmentation fault? > >>>> Thank you, > >>>> Sid. > > >>>> On Tue, Sep 6, 2011 at 11:34 PM, ankush garg <[email protected]>wrote: > > >>>>> better contact AKSHAY CHADHA .. the person is quite good at c and > >>>>> algos.... currently placed in MICROSOFT.. > >>>>> [email protected] > >>>>> 9899466888 > > >>>>> -- > >>>>> You received this message because you are subscribed to the Google > >>>>> Groups "Algorithm Geeks" group. > >>>>> To post to this group, send email to [email protected]. > >>>>> To unsubscribe from this group, send email to > >>>>> [email protected]. > >>>>> For more options, visit this group at > >>>>>http://groups.google.com/group/algogeeks?hl=en. > > >>> -- > >>> You received this message because you are subscribed to the Google Groups > >>> "Algorithm Geeks" group. > >>> To post to this group, send email to [email protected]. > >>> To unsubscribe from this group, send email to > >>> [email protected]. > >>> For more options, visit this group at > >>>http://groups.google.com/group/algogeeks?hl=en. > > >> -- > >> You received this message because you are subscribed to the Google Groups > >> "Algorithm Geeks" group. > >> To post to this group, send email to [email protected]. > >> To unsubscribe from this group, send email to > >> [email protected]. > >> For more options, visit this group at > >>http://groups.google.com/group/algogeeks?hl=en.
-- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
