O(n^5)

more interesting will be to find exact number of iterations ...

On Sep 10, 10:48 am, siddharam suresh <[email protected]> wrote:
> first loop n
> send loop n^2
> third loop n(i m not sure)
> so  n^4
> Thank you,
> Sid.
>
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> On Sat, Sep 10, 2011 at 11:09 AM, ravi maggon <[email protected]> wrote:
> > I think it should be n^3
>
> > On Sat, Sep 10, 2011 at 10:51 AM, Neha Singh 
> > <[email protected]>wrote:
>
> >> O(n^5)
>
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> > Regards
> > Ravi Maggon
> > Final Year, B.E. CSE
> > Thapar University
>
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