@Ankit. n=0000 1101
i=2 j=3 x = (2^j + 2^i) = 0000 1100 x^n = 0000 0001 Answer should be 0000 1101. On Wed, Sep 14, 2011 at 12:39 AM, Ankit Agarwal <[email protected]>wrote: > let x = 2^j + 2 ^i > new number after swapping the digits is x XOR n > > eg n = 0000 1101 > j = 6 i = 2 > x = 0100 0100 > new number = x XOR n = 0100 1001 > > > -- > Ankit Agarwal > Computer Science & Engg. > Integrated Dual Degree, V yr > Department of Electronics & Computer Engineering > Indian Institute of Technology Roorkee > Ph. no. +91-9580098805 > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- *Sandeep Kumar,* ( Mobile +91-9866507368 *“I believe in smart work, Believe Me”* -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
