*//this method can be applied only when
the value of elements in array are not very large

int count[];

for(i = 0 to n-1)
  {
    if(count[arr[i]] == 1)
      printf(" %d ", arr[i]);
    else
     count[arr[i]]++;
  }*


..

On Wed, Aug 31, 2011 at 12:38 PM, Yuchen Liao <[email protected]> wrote:

> Hi Akshat,
>
>     I think that you are wrong here. For example, I have 1, 1, 2 in the
> array. The output will be 2. But not 1.
>
>
>
> On Wed, Aug 31, 2011 at 1:57 AM, Akshat Sapra <[email protected]>wrote:
>
>> Solution:
>>
>> arr[n],sum = 0;
>>
>>
>> for ( int i = 0 ; i < n; i++ ) {
>>        sum ^= arr[i];
>> }
>>
>> print sum; // required number
>>
>> --
>>
>>
>> Akshat Sapra
>> Under Graduation(B.Tech)
>> IIIT-Allahabad(Amethi Campus)
>> --------------------------------------
>> [email protected]
>> [email protected]
>> [email protected]
>> [email protected]
>>
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>
>
>
> --
> from Yuchen Liao via Gmail
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