>
>
>
On Friday, 16 September 2011 13:25:38 UTC+5:30, Anup wrote:
>
> #include<stdio.h>
> int main()
> {
> int a[5]={1,2,3,4,5};
> int *ptr=(&a + 1);
>
       int *ptr=(int *)(&a + 1);

> printf("%d %d\n",*(a+1),*(ptr-1));
> return 0;
> }
>
> Find the output!
>

Now it will print 2 5 

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