When you pass an array as a formal parameter in a function, it decays to a
pointer, so it is mandatory for you to send in the length of the array as
well.

On Fri, Sep 16, 2011 at 9:06 PM, sukran dhawan <[email protected]>wrote:

> not possible
>
>
> On Fri, Sep 16, 2011 at 12:17 PM, tech coder <[email protected]>wrote:
>
>> +1 to don
>>
>>
>> On Thu, Sep 15, 2011 at 9:40 PM, Don <[email protected]> wrote:
>>
>>> Not really. Usually you would need a second parameter indicating the
>>> size of the input. In theory it might be possible to put a marker
>>> value at the end of the array.
>>>
>>> Most implementations of malloc store the size of the memory block in
>>> the word immediately before the returned address. This is used when
>>> you free the memory. So some programmers use things like:
>>>
>>> int *data = (int *)malloc(n*sizeof(int));
>>>
>>> And then later:
>>> int size = *(data-4)/sizeof(int);
>>>
>>> This would not work if data was declared as an array rather than as a
>>> malloced pointer. It is also completely implementation dependent, so I
>>> would not recommend it for any code which someone may someday have to
>>> maintain.
>>>
>>> Don
>>>
>>> On Sep 15, 10:59 am, rahul vatsa <[email protected]> wrote:
>>> > if i pass an int array to a function, is it possible to find out the no
>>> of
>>> > elements in the called function ?
>>>
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>>
>>
>> --
>> *
>>
>>  Regards*
>> *"The Coder"*
>>
>> *"Life is a Game. The more u play, the more u win, the more u win , the
>> more successfully u play"*
>>
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-- 
Anup Ghatage

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