i=0;
char *str;
while(a[i]!=NULL)
{
j=0;
while(j!=i)
{
for(k=j;k<=i;k++)
{
l=0;
str[l]=a[j];
}
if(Dictionary.findword(str))
printf(str);
j++;
}
}
...
On Mon, Sep 19, 2011 at 8:20 PM, Sangeeta <[email protected]> wrote:
> given an array of characters without spaces and a dictionary.All valid
> dictionary words must be found and printed.
> i/p : BANKERKCATXYWOMAN.
> o/p: BANK
> BANKER
> CAT
> WOMAN
> MAN
> (the only function you could use for dictionary is
> dictionary.findword(char *str) which returns a Boolean value).
> Eg. Dictionary.findword(“bank”) =>true
> Dictionary.findword(“hj”) =>false
>
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