its O(nlogn) only...
n v cant directly access d leaf element...
since d leaf elements are n(n-1)/2....so last dese many elemnts will found n
compared...



Regards,
PAYAL GUPTA,
CSE-3rd yr
NIT_B

On Tue, Sep 20, 2011 at 10:54 PM, saurabh agrawal <[email protected]>wrote:

> How will you directly access the leaf nodes, you dont have the heap
> implementation, you are just provided with the API. :)
>
>
>
> On Tue, Sep 20, 2011 at 9:55 PM, sukran dhawan <[email protected]>wrote:
>
>> o(n)
>>
>>
>> On Tue, Sep 20, 2011 at 6:42 PM, CHERUVU JAANU REDDY <
>> [email protected]> wrote:
>>
>>>
>>> We can find minimum element in O(n) time.
>>>
>>> Just compare leaf nodes in max heap tree.
>>>
>>>
>>>
>>> Cheers
>>> Janardhan Reddy Cheruvu
>>> +91-9642421117
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>> On Tue, Sep 20, 2011 at 6:39 PM, saurabh agrawal 
>>> <[email protected]>wrote:
>>>
>>>> I think, we have to delete all the elements from the heap which takes
>>>> o(n*logn). Please share if you have any better solutions.
>>>>
>>>> On Tue, Sep 20, 2011 at 6:38 PM, saurabh agrawal 
>>>> <[email protected]>wrote:
>>>>
>>>>> What is the time to get min element from the binary max heap !!
>>>>> You might be given the heap as API. I mean, you dont have
>>>>> implementation of the heap.
>>>>>
>>>>
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