let x be the number initialize ans to some value like x or x/2 now repeatedly do the following ans = (ans + x/ans)/2 each time you perform this operation you will move closer to the sqrt value and depending upon the precision required stop
On Sat, Sep 24, 2011 at 11:17 PM, siddharth srivastava <[email protected]>wrote: > > > On 24 September 2011 13:45, shady <[email protected]> wrote: > >> one of the simplest way is to do binary search... :) > > > +1 > > >> >> >> On Sat, Sep 24, 2011 at 8:42 PM, teja bala <[email protected]>wrote: >> >>> http://www.geeksforgeeks.org/archives/3187 >>> >>> >>> check dis one............. >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "Algorithm Geeks" group. >>> To post to this group, send email to [email protected]. >>> To unsubscribe from this group, send email to >>> [email protected]. >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > Regards > Siddharth Srivastava > > > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Sunny Aggrawal B.Tech. V year,CSI Indian Institute Of Technology,Roorkee -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
