that would be (n+9)C(n)..

On Sep 25, 10:05 pm, shady <[email protected]> wrote:
> @sanjay can you please tell how did you arrive at that solution ?
>
>
>
>
>
>
>
> On Sun, Sep 25, 2011 at 12:32 PM, Yogesh Yadav <[email protected]> wrote:
> > +1 Gohana....
>
> > On Sun, Sep 25, 2011 at 12:28 PM, Sanjay Rajpal <[email protected]> wrote:
>
> >> let the number of digits be n
> >> then answer would be ((n+9)! ) / (9! * n!)
>
> >> Sanju
> >> :)
>
> >> On Sat, Sep 24, 2011 at 11:51 PM, Yogesh Yadav <[email protected]> wrote:
>
> >>> mistake in last post...it was not factorial....sum upto n i.e =n(n+1)/2
>
> >>> i.e 10! is wrong ...it will be 10(10+1)/2
>
> >>> ....
> >>>   On Sun, Sep 25, 2011 at 12:14 PM, Yogesh Yadav <[email protected]>wrote:
>
> >>>>        n=1     n=2       n=3       n=4
> >>>>          0        10        10!        (10!)!
> >>>>          1          9          9!         (9!)!
> >>>>          2          8          8!
> >>>>          3          7          7!
> >>>>          4          6          6!
> >>>>          5          5          5!
> >>>>          6          4          4!
> >>>>          7          3          3!
> >>>>          8          2          2!
> >>>>          9          1          1!
> >>>> sum  10         55        220      and so on....
>
> >>>> On Sun, Sep 25, 2011 at 11:46 AM, Sanjay Rajpal <[email protected]>wrote:
>
> >>>>>  Can you plz tell the answer for
> >>>>> for 3 answer=?
> >>>>> nd for 4 answer=?
> >>>>> Sanju
> >>>>> :)
>
> >>>>> On Sat, Sep 24, 2011 at 10:39 PM, Dheeraj Sharma <
> >>>>> [email protected]> wrote:
>
> >>>>>> can u plz be more..clear ..with wat the input will consist of..
> >>>>>> wat does this mean
> >>>>>> "for 2 answer=55"
> >>>>>> does that mean..that how many non decreasing digits can be formed by 2
> >>>>>> digit num
>
> >>>>>> On Sun, Sep 25, 2011 at 1:08 AM, shady <[email protected]> wrote:
>
> >>>>>>> A number is said to be made up of non-decreasing digits if all the
> >>>>>>> digits to the left of any digit is less than or equal to that digit. 
> >>>>>>> for eg.
> >>>>>>> 1122, 234, 2
>
> >>>>>>> 0000, 0011 is a possible 4 digit non decreasing number
>
> >>>>>>> so given a number n, how many n digit numbers exist ?
>
> >>>>>>> for 2 answer = 55
>
> >>>>>>> Can someone post complexity and their approach....
>
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> >>>>>> --
> >>>>>> *Dheeraj Sharma*
> >>>>>> Comp Engg.
> >>>>>> NIT Kurukshetra
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