for the first instruction : 150+5+120+5+160+5+140=585 ns
for the rest of the instructions , though pipeline----
max(150,120,160,140)=160

(160+5)*999=164835 ns
 we assume that there will be no extra stalls existed in our system
---------585 + 164835 =165420 ns =165.4 us...
correct me if I'm wrong .........

On Sun, Sep 25, 2011 at 9:25 AM, siva viknesh <sivavikne...@gmail.com>wrote:

> A 4-stage pipeline has the stage delays as 150, 120, 160 and 140 ns
> (nano seconds)
> respectively. Registers that are used between the stages have a delay
> of 5 ns each. Assuming
> constant clocking rate, the total time taken to process 1000 data
> items on this pipeline will
> approximately be
> a. 120 us (micro seconds)
> b. 165 us
> c. 180 us
> d. 175 us
>
> ...plz give detailed explanation for the ans
>
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