sorry :D
int RepChar(char *str)
{
int i,j;
int ret = -1;
int count[25];
for (i=0;i<25;++i) {
count[i]=0;
}
for (i=0;str[i];++i) {
j=str[i] - 'a';
count[j]++;
}
for (i=0;str[i];i++) {
if (count[i]==1) {
return ('a'+i);
}
}
return ret;
On Wed, Sep 28, 2011 at 8:10 PM, Shravan Kumar <[email protected]> wrote:
> @Sukran
>
> I guess it will return repeating character in alphabetical order but not in
> order of appearance in the i/p ??
>
>
> On Wed, Sep 28, 2011 at 8:04 PM, sukran dhawan <[email protected]>wrote:
>
>> int RepChar(char *str)
>> {
>> int i,j;
>> int ret = -1;
>> int count[25];
>>
>> for (i=0;i<25;++i) {
>> count[i]=0;
>> }
>> for (i=0;str[i];++i) {
>> j=str[i] - 'a';
>> count[j]++;
>> }
>> for (i=0;i<25;i++) {
>> if (count[i]==1) {
>> return ('a'+i);
>> }
>> }
>> return ret;
>>
>> }
>>
>> On Wed, Sep 28, 2011 at 7:57 PM, shady <[email protected]> wrote:
>>
>>> i will mail the code by tomorrow.
>>>
>>>
>>> On Wed, Sep 28, 2011 at 6:54 PM, Avenged <[email protected]> wrote:
>>>
>>>> Bump. Anybody?
>>>>
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