1. don't use dev c 2. search archives 3. after doing 2 you will say it is not there, therefore solution by sunny -
char five[7] -> string of length 7 charlie -> 7 length string declare it as char[8] u will get expected output On Sat, Oct 8, 2011 at 4:14 PM, SHIVAM AGRAWAL <[email protected]> wrote: > when i am running this on dev c it is printing times but on running in > linux it is not printing times plz any1 xplain me y is it so???? > > > #include<stdio.h> > main() > { > char outline[50]; > char one[7],two[7],four[7],five[7]; > int three; > sprintf(outline,"this is %d tim %s \n",10,"charlie"); > printf("%s",outline); > sscanf(outline,"%s %s %d %s %s",&one,&two,&three,&four,&five); > printf("%s\n",one); > printf("%s\n",two); > printf("%d\n",three); > printf("%s\n",four); > printf("%s\n",five); > } > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
