Nopes
Still it does not ensure that duplicates will not be there in the priority
queue
what i mean is you cannot write directly
do k times{
data = pop()
// let i,j are row and col of data
push(i+1,j);
push(i,j+1);
}
you need to add the following checks
if((i+1,j) is not in the heap) push(i+1,j)
if((i,j+1) is not in the heap) push(i,j+1)
because heap does not automatically check for duplicates
and to check for duplicates we need an extra data structure other than heap,
which stores that which (i+1,j) are already there in the heap map can also
be used so overall complexity will go O(k* lg^2K)
On Thu, Oct 13, 2011 at 12:26 PM, anshu mishra <[email protected]>wrote:
> struct data
> {
> int row, col,
> int val;
> };
>
> priority_queue<data> heap;
>
> now fine?
>
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Sunny Aggrawal
B.Tech. V year,CSI
Indian Institute Of Technology,Roorkee
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