already been answered... :-/
but have to say you are damn quick...

On Sat, Oct 15, 2011 at 12:03 PM, Bittu Sarkar <[email protected]> wrote:

> Q7. Correct answer is 12km west and 12km south for sure!!
>
>
> On 21 September 2011 13:28, Nitin Garg <[email protected]> wrote:
>
>> Ohh i totally missed that line.
>> Thanx a lot :)
>>
>>
>> On Wed, Sep 21, 2011 at 10:46 AM, pankaj agarwal <
>> [email protected]> wrote:
>>
>>> @Nitin Garg
>>>
>>> Question 6 -
>>>
>>> i agree that greater the sum is and greater the probability to getting
>>> it.
>>> but in given question if sum>100 then rolling is stopped
>>> so for
>>>
>>> P(106)=P(100)*1/6
>>> P(105)=P(100)*1/6+P(99)*1/6
>>> .
>>> .
>>> .
>>> P(101)=P(100)*1/6+P(99)*(1/6)+P(98)*(1/6)+P(97)*(1/6)+..+P(95)*(1/6)
>>>
>>> now P(101) is more
>>>
>>> cleare me if something is wrong.
>>>
>>>
>>>
>>> On Mon, Sep 19, 2011 at 1:35 PM, Nitin Garg 
>>> <[email protected]>wrote:
>>>
>>>> Question 6 -
>>>> Intuitively you can see that the greater the sum is, the greater the
>>>> favorable events in sample space.
>>>>
>>>> e.g. - sum = 1 .. cases {(1)}   Pr = 1/6
>>>> sum = 2             cases {(2),(1,1)}   Pr = 1/6 + 1/36
>>>> sum = 3            cases {(3),(2,1)(1,2)(1,1,1)}  Pr = 1/6 + 1/36 +1/36
>>>> + 1/216
>>>>
>>>>
>>>> for a more formal proof, look at the recursion -
>>>>
>>>>
>>>> P(k) = (P(k-6) + P(k-5) + P(k-4)... P(k-1)))/6
>>>>
>>>> where P(0) = 1, P(i) = 0  for i<0
>>>>
>>>> Base case -
>>>> P(2) > P(1)
>>>>
>>>> Hypothesis -
>>>>
>>>> P(i) > P(i-1) for  all i <= k
>>>>
>>>> To prove
>>>> P(k+1)  > P(k)
>>>>
>>>> Proof
>>>> P(k+1) - P(k) = (P(k) - P(k-6))/6 > 0
>>>>
>>>>
>>>>
>>>
>>>
>>>
>>>>  --
>>>>      Pankaj Agarwal
>>>>      Communication and Computer Engineering
>>>>      LNMIIT,jaipur
>>>>
>>>>  --
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>>
>>
>>
>> --
>> Nitin Garg
>>
>> "Personality can open doors, but only Character can keep them open"
>>
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>
>
>
> --
> Bittu Sarkar
> 5th Year Dual Degree Student
> Department of Computer Science & Engineering
> Indian Institute of Technology Kharagpur
>
>
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