This can be done by backtracking....easily...

With regards,

Praveen Raj
DCE-IT 3rd yr
9999735993
[email protected]



On Wed, Sep 28, 2011 at 11:30 PM, rashmi i <[email protected]> wrote:

>
> 1. Datacenter Cooling
>
> We have some rooms in our datacenter, and we need to connect them all with
> a single cooling duct.
>
> Here are the rules:
>
>    - The datacenter is represented by a 2D grid.
>    - Rooms we own are represented by a 0.
>    - Rooms we do not own are represented by a 1.
>    - The duct has to start at the air intake valve, which is represented
>    by a 2.
>    - The duct has to end at the air conditioner, which is represented by a
>    3.
>    - The duct cannot go in multiple directions out of the intake or the AC
>    - they must be the two endpoints of the duct.
>    - The duct must pass through each room exactly once.
>    - The duct cannot pass through rooms we do not own.
>    - The duct can connect between rooms horizontally or vertically but not
>    diagonally.
>
> Here is an example datacenter:
>
> 2  0  0  0
>
> 0  0  0  0
>
> 0  0  3  1
>
>
> There are two possible ways to run the duct here:
>
> 2--0--0--0
>          |
> 0--0--0--0
> |
> 0--0--3  1
>
> or
>
> 2  0--0--0
> |  |     |
> 0  0  0--0
> |  |  |
> 0--0  3  1
>
> Write a program to compute the number of possible ways to run the duct. For
> the above example, the correct answer is 2.
> Input format:
>
> Your program should read from stdin. The input will be a series of integers
> separated by whitespace.
>
> The first two integers will be W and H, with width and height of the
> datacenter. These will be followed by W*H more integers, specifying the 2D
> grid representing the datacenter.
> Output format:
>
> Your program should write a single integer out to stdout: the number of
> possible ways to run the duct.
>
> See how fast you can make it.
>
> Our best solution (written in C) can solve the following test case in under
> 5 seconds on a 2.4GHz Pentium 4, but it's pretty good if you can get to
> within 1-2 orders of magnitude of that.
>
> 7 8
> 2 0 0 0 0 0 0
> 0 0 0 0 0 0 0
> 0 0 0 0 0 0 0
> 0 0 0 0 0 0 0
> 0 0 0 0 0 0 0
> 0 0 0 0 0 0 0
> 0 0 0 0 0 0 0
> 3 0 0 0 0 1 1
>
>
>
> --
> R@$!-!
> "DoN'T LimIt Ur cHaLlEngeS, ChAlLenGe uR LImItS."
>
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