Are we talking about only positive integers here?

On Wed, Oct 26, 2011 at 11:33 PM, Vaibhav Mittal
<[email protected]>wrote:

> +1 Prem
> @ligerdave : I knew about the recursion method..but can u throw some light
> on the pointer based method..(with a small example maybe)..
> Specifically I wanted to know the implementation part and the running time
> of the algorithm.
>
>
> On Wed, Oct 26, 2011 at 8:33 PM, ligerdave <[email protected]> wrote:
>
>> @meng You already have the pattern figured out. each time subtract 1
>> from the lowest digit and add to higher digit(only once), until the
>> lowest digit equals to closest higher digit. the selection of which
>> number to start could be figured out with given parameters sum and
>> combination
>>
>> @Prem, no recursion needed here. it make it more complex than
>> necessary. one loop with a pointer should be able to resolve this
>>
>> On Oct 24, 6:28 pm, Meng Yan <[email protected]> wrote:
>> > Hi, my question is
>> >
>> > given sum=N and combination constraint=M (the number of elements), how
>> to
>> > find all possible combinations of integers?
>> >
>> > For example, given sum=6, combination=3; how to get the result as
>> following:
>> > 1+1+4;
>> > 1+2+3;
>> > 2+2+2;
>> >
>> > We don't care about order of the elements, which means 1+1+4 and 1+4+1
>> are
>> > considered as same combination.
>> >
>> > Thanks a lot!
>> >
>> > Meng
>>
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