+1 abhishek

On Mon, Oct 31, 2011 at 6:26 PM, abhishek kumar <[email protected]> wrote:

> Represent the dependencies as a graph. Store all the values in a list. For
> each vertex in the graph find all values for which there is no edge from
> the vertex. If these values are there in the list, remove them from the
> list and create a set of the vertex and the removed values.
> If the values are not there in the list then create a set with the vertex
> only. Do this for all the vertices.
>
>
> On Mon, Oct 31, 2011 at 5:51 PM, Bharath 2009503507 CSE <
> [email protected]> wrote:
>
>> Given a set of values..in which there are some dependencies..
>>
>> Eg..  x y z a b
>>
>> Dependencies: x,y
>> a,z
>>
>> Note that dependency is not transitive..Is it possible to separate
>> these elements into sets such that no two elements in the same set are
>> dependant and we should end up with the least number of sets..
>>
>> I could not find a good solution for this..Please help me..
>>
>> Regards,
>>
>> Bharathwajan
>>
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