@vikas

ur algo will search for 1st element of 1d in whole 2d array,
on worst case u'll search it in n^2, then search for all 1d elements
in 2d in O(n)
so whole complexity goes to  O(n^2 +n)
it can be reduced if we use hashing of 1d array, and count_found
and while searching for 1st element of 1d in 2d array, if it's found
make temp[i][j] as true(even though its not first element) and false
if its not in 1d hash, and increase count_found
this will reduce to O(n^2)

surender

On 11/1/11, vikas <[email protected]> wrote:
> ok,
> so do it like this;
> 1. create boolean array
>       boolean temp[][] = new boolean[row][column];
>       init(temp, true);
>
> 2. traverse the array for the 1d array of 0th index and then a
> recursive search
> if search fails, or position already contains false, return and search
> again
>
> boolean search(int searchArray[][], int givenArray[], int rpos, int
> cpos, int gpos){
>    if(gpos > givenArray.len) return false;
>    if(temp[rpos][cpos] == false) return false;
>    if(searchArray[rpos][cpos] == givenArray[gpos])
>         {
>                temp[rpos][cpos] = search(searchArray, givenArray, rpos
> +1, cpos, gpos+1)|
>                                                  search(searchArray,
> givenArray, rpos-1, cpos, gpos+1) |
>                                                  search(searchArray,
> givenArray, rpos, cpos+1, gpos+1)|
>                                                  search(searchArray,
> givenArray, rpos+1, cpos-1, gpos+1)
>         }
>       if(temp[rpos][cpos]) return true;
>      if(cpos < searchArray.len)
>        search(searchArray, givenArray, rpos, cpos+1, 0);
>     else
>       search(searchArray, givenArray, rpos+1, 0, 0);
>
> }
>
> On Nov 1, 4:25 pm, SAMM <[email protected]> wrote:
>> For example :-
>>
>> 2d array ::
>>
>> 1  2  3   4    5    6
>> 7   8  9  10 11 12
>> 13 14 15 16 17 18
>> 19 20 21 22 23 24
>>
>> we hav 1d array as :-- 13 2 21 10 23 12
>>
>> So the 1d array is a subset of 2d array ...
>>
>> On 11/1/11, vikas <[email protected]> wrote:
>>
>>
>>
>> > what do you mean by subset of 1D present in the 2D array? is it
>> > something like 3245 , the search may be 3245/ 24/ 45/ .... all 16
>> > subsets need to be searched?
>>
>> > On Oct 28, 12:02 pm, SAMMM <[email protected]> wrote:
>> >> How do u plan to implement it ???
>>
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>> --
>> Somnath Singh
>
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