we can get it by ceil(log2n)

On Mon, Nov 14, 2011 at 8:38 PM, Don <[email protected]> wrote:

> Can you define the question more precisely?
> Do you want the largest power of 2 <= n, or the largest power of two
> which divides into n?
> In the first case, it is the number of digits after the leftmost 1 in
> the binary representation.
> In the latter case, it is the number of trailing zeros in the binary
> representation.
> Don
>
> On Nov 14, 12:06 am, Ankur Goel <[email protected]> wrote:
> >  How to find highest power of 2 in an integer
> >
> > Suppose number is
> > 00001 - Highest power of 2 is 1
> > 00011 - Highest power of 2 is 2
> > 11000 - Highest power of 2 is 5
> >
> > No loops
>
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-- 
*UTKARSH SRIVASTAV
CSE-3
B-Tech 3rd Year
@MNNIT ALLAHABAD*

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