@kunzmilan :
Can u please maintain the clarity ??
How did u find the M

if the list is 4 2 8 9  5 1 9 how M looks like ?? please elaborate it...

On 24 November 2011 06:15, kunzmilan <kunzmi...@atlas.cz> wrote:

>
>
> On 24 lis, 09:09, kumar raja <rajkumar.cs...@gmail.com> wrote:
> > @kunzmilan : i did not get  u, once explain with example...
> >
> > On 23 November 2011 23:47, kunzmilan <kunzmi...@atlas.cz> wrote:
> Matrix M
> 0 1 0
> 0 1 0
> 1 0 0
> multiplied with M(T)
> 0 0 1
> 1 1 0
> 0 0 0
> gives
> 1 0 0
> 0 2 0
> 0 0 0.
> On its diagonal are numbers of repeated elements.
> kunzmilan
>
> >
> >
> >
> >
> >
> >
> >
> >
> >
> >
> >
> > > On 24 lis, 07:02, kumar raja <rajkumar.cs...@gmail.com> wrote:
> > > > In the given array all the elements occur single time except  one
> element
> > > > which occurs  2 times find it in O(n) time and O(1) space.
> >
> > > > e.g.  2 3 4 9 3 7
> >
> > > > output :3
> >
> > > > If such a solution exist can we extend the logic to find "All the
> > > repeated
> > > > elements in an array in O(n) time and O(1) space"
> >
> > > > --
> > > > Regards
> > > > Kumar Raja
> > > > M.Tech(SIT)
> > > > IIT Kharagpur,
> > > > 10it60...@iitkgp.ac.in
> > > > Write the list in the form of a matrix M, e.g.
> > > > 0 1 0 0...
> > > > 0 0 1 0...
> > > > 0 0 0 1...
> > > > ......etc.,
> > > > and its quadratic form M(T)M shows, how many times each element
> repeats.
> > > kunzmilan
> >
> > > --
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> >
> > --
> > Regards
> > Kumar Raja
> > M.Tech(SIT)
> > IIT Kharagpur,
> > 10it60...@iitkgp.ac.in
>
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-- 
Regards
Kumar Raja
M.Tech(SIT)
IIT Kharagpur,
10it60...@iitkgp.ac.in

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