Thank u, I got it.....

On Thu, Dec 1, 2011 at 1:15 PM, Sri Harsha <[email protected]> wrote:

> 10 dequeue operations and 9 enqueue operations. the extra dequeue is to
> pop. the 9 dequeues are to remove from this queue and 9 enqueues to insert
> into the 2nd queue
>
> On Thu, Dec 1, 2011 at 11:51 AM, Vijay Khandar <[email protected]>wrote:
>
>> A stack is implemented with two queues then what are the minimum
>> enqueue and dequeue operations needed to perform for pop
>> operation,where '10' elements are already in the first queue?
>>
>>
>> please anyone provide soln with explation.........
>>
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>
>
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> *Regards*,
> *Sri Harsha*
>
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