@shady

Just an addition to the previous solution, in case u are not concerned
about overlapping string i.e orig and rev strs overlap then all you
need to do is remove the following condition and it shall work fine:

*(pStrt < pRev)  // remove this condition..


On 30 Dec, 15:03, atul anand <[email protected]> wrote:
> @shady : for this question
>
> Given a string of length N, find whether there exits an even length
>  reverse substring of a substring.
>
> you can use hastable , as i have mentioned above.
>
>
>
>
>
>
>
> On Thu, Dec 29, 2011 at 5:50 PM, shady <[email protected]> wrote:
> > oh, i didn't read all the posts, anyway i have understood lucifier's
> > O(n^2) time solution.
>
> > and ya what's the solution for this question?
> > Given a string of length N, find whether there exits an even length
> >  reverse substring of a substring.
>
> > On Thu, Dec 29, 2011 at 2:23 PM, atul anand <[email protected]>wrote:
>
> >> @shady : lets go with this one:-
>
> >> given string = *abcdrdcba
>
> >> abcd != dcba  -  not a palindrome
> >> **abcd != dcba - **not a palindrome *
> >> *
> >> *no even length palindrome found for the given string.
>
> >> given string = ab*cddc*abr
>
> >> even lenght palindrome found = cddc
>
> >> if another even length palindrome found report the longest one.
>
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