hi...i gues u getting confused vth d last character o/p 4m d last
printf...so i guess dat i'll be cleared..if u jst modify ur test
string......
chk dis out
main()
{
char ch[]="ABCP";
char *s;
s=ch;
printf("%c",*s++);
printf("%c",*++s);
printf("%c",++*s);
}
d last printf isnt printin d D vich is d last character bt d value after
incrementin wen d pointer still points 2 d charactr "C" in string...
hope i was clear @ xplainatn...
Regards,
PAYAL GUPTA,
NIT-BHOPAL.
On Sat, Jan 14, 2012 at 3:10 PM, om prakash yadav <
[email protected]> wrote:
> main()
> {
> char ch[]="ABCD";
> char *s;
> s=ch;
> printf("%c",*s++);
> printf("%c",*++s);
> printf("%c",++*s);
> }
>
> Can anyone plz tell me the concept behind output??
>
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