correction:
yes it O(1) space , as we can revert back the sum of rows(0 to 1 , 0 to 2 ,
1 to 2 , 2 to 3 ,3 to 4 etc etc combination) in O(col) time.

On Wed, Jan 18, 2012 at 11:25 PM, atul anand <[email protected]>wrote:

> @ sravanreddy001 : yes it O(1) space , as we can revert back the sum of
> rows(0 to 1 , 0 to 2 , 1 to 2 , 2 to 3 ,3 to 4 etc etc combination) in
> O(row) time.
> actually that's the trick for converting O(n^4) to O(n^3) complexity.
>
> naive brute force seems O(n^6) to me.
>
>
>
>
> On Wed, Jan 18, 2012 at 11:14 PM, sravanreddy001 <[email protected]
> > wrote:
>
>> @atul:
>> I got this now... very good one... the space is O(1) right, as what ever
>> the the values we store in matrix, can be reverted back in similar way..
>>
>> i haven't thought of the kadane's algo that comes within the inner loop,
>>
>> the O(n^4) solution i thought will search brutefocely in the inner loops,
>> leading additional loop, also my new matrix construction goes along a
>> different appraoch, where as yours is lot simple.
>>
>> Is the bruteforce solution for this O(n^6) ?
>>
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