@lucifer: my bad ...thanks a lot

On Sun, Jan 22, 2012 at 4:27 PM, Lucifer <[email protected]> wrote:

> @Arun..
>
> I think you are generating the bin-tree for ' i =startIndex' and not '
> i =startIndex +1'..
>
> Hence, if you just trace it for ' i =startIndex + 1' for all the
> recursive calls, you should get it...
>
> On Jan 23, 5:22 am, Lucifer <[email protected]> wrote:
> > @Arun...
> >
> > You are not getting it wrong but then you have just generated one
> > binary tree..
> >
> > What about the other bin-trees...?
> > The bin-tree that you are generating is for the first recursive
> > iteration..
> >
> > Let me give you a quick explanation...
> >
> > "GenerateBT" has the following loop..
> > for (int i =startIndex ; i <=endIndex; ++i)
> > {}
> >
> > Now, the bin-tree that you are generating is for i = startIndex + 1,
> > and also when you recursively go inside you are basically tracing it
> > for 'i = startIndex + 1'..
> >
> > Try doing it for i = startIndex + 3 (say)..
> > and also ensure that when you go inside recursively try to trace the
> > case where 'i > startIndex + 1'
> >
> > and see if you get it..
> >
> > On Jan 23, 5:11 am, Arun Vishwanathan <[email protected]> wrote:
> >
> >
> >
> >
> >
> >
> >
> > > @lucifer: sorry if i seem to be missing the ppoint...can u just clarify
> > > what I am getting wrong here..
> >
> > > if array is a[0] a[1] a[2] a[3] a[4] say, i understand yr recursion
> goes as
> > > follows:
> > > the first node data is a[0], its left pointer is null ( since call is
> made
> > > with startindex=1 and lastindex =0 and so null is returned ) and its
> right
> > > pointer points to node whose data is a[1], whose left pointer is null
> > > (since call made with startindeex =2 and lastindex =1 )and whose right
> > > pointer points to node whose data is a[2] whose left pointer is null
> and
> > > right points to node whose data is a[3] and so on..
> > > am sorry if it sounds silly...can u clarify if am seeing it wrong??
> >
> > > On Sun, Jan 22, 2012 at 3:31 PM, Lucifer <[email protected]>
> wrote:
> > > > @Arun..
> >
> > > > Are you referring to the following condition in 'GenerateBT':
> > > > /*
> > > >  if ( startIndex > endIndex) return NULL;
> > > > */
> >
> > > > If so, then answer is no. The above condition basically identifies
> > > > that we have reached a leaf node and hence, the leaf node should have
> > > > both its left and right pointers set to NULL.
> >
> > > > If you trace it. you will figure it out.
> > > > In case there is a doubt do let me know..
> >
> > > > On Jan 23, 4:17 am, Arun Vishwanathan <[email protected]>
> wrote:
> > > > > @lucifer: in yr code will not all the root->left be NULL for each
> > > > iteration
> > > > > as
> > > > > startindex is always greater than endindex ( i.e i-1) in the
> recursive
> > > > > function call??and so for each node only root->right is made?
> >
> > > > > On Fri, Dec 30, 2011 at 12:51 AM, praveen raj <
> [email protected]>
> > > > wrote:
> > > > > > yes... right...
> > > > > > i forget to remove this statement......
> >
> > > > > > PRAVEEN RAJ
> > > > > > DELHI COLLEGE OF ENGINEERING
> >
> > > > > > On Fri, Dec 30, 2011 at 2:17 PM, Lucifer <[email protected]
> >
> > > > wrote:
> >
> > > > > >> @praveen
> >
> > > > > >> I think what u are doing above is the following:
> > > > > >> Say, F(n) denotes the no. of binary trees that can be formed
> using N
> > > > > >> elements given the inorder sequence..
> >
> > > > > >> F(n) = SumOver(i= 1 to N) { F(i-1) * F(N-i) }
> >
> > > > > >> which is nothing but..
> > > > > >> F(N) = (2n C n)/ (n+1) i.e. catalan's no.
> >
> > > > > >> Also, i would like to mention that in ur code probably u need to
> > > > > >> remove the following condition otherwise u result outcome will
> always
> > > > > >> be zero..
> >
> > > > > >> *
> > > > > >> if(N==0) return 0;
> >
> > > > > >> On 30 Dec, 13:41, praveen raj <[email protected]> wrote:
> > > > > >> > int countBT(int N)
> > > > > >> > {
> > > > > >> >   int count =0;
> > > > > >> >   int count1;
> > > > > >> >   if(N==0)
> > > > > >> >      return 0;
> > > > > >> >    if(N<=1)
> > > > > >> >      return 1;
> > > > > >> >      else
> > > > > >> >    {
> > > > > >> >        for(int j=1;j<=N;j++)
> > > > > >> >        {
> > > > > >> >           count1 = countBT(j-1)
> > > > > >> >           count2 =countBT(N-j);
> > > > > >> >           count+=(count1*count2);
> > > > > >> >         }
> > > > > >> >           return (count);
> > > > > >> >     }
> >
> > > > > >> > }
> >
> > > > > >> > PRAVEEN RAJ
> > > > > >> > DELHI COLLEGE OF ENGINEERING
> >
> > > > > >> --
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