+1
*
Sanjay Kumar
B.Tech Final Year
Department of Computer Engineering
National Institute of Technology Kurukshetra
Kurukshetra - 136119
Haryana, India
Contact: +91-8053566286
*



On Thu, Jan 26, 2012 at 6:28 PM, Ashish Goel <[email protected]> wrote:

> replace all 0s by -1
> keep additional array to get the sumHere at every position of all -1s and
> 1s.
>
> say you got
>          0  1  0 1  0  0  0  0 1 1 1 1  0
>         -1 1 -1 1 -1 -1 -1 -1 1 1 1 1 -1
> sum -1 0 -1 0 -1 -2 -3 -4 -3 -2 -1 0 -1
>
> all equal numbers in sum shows equal zeros and 1s between then including
> the end( between two -2 or two -3 or 0 0r -1) so biggest one can be figured
> out easily use a hash to store these cum sum, store their first and
> last occurrence, walk over to get max diff.
>
>
>
>
>
> Best Regards
> Ashish Goel
> "Think positive and find fuel in failure"
> +919985813081
> +919966006652
>
>
>
> On Fri, Jan 27, 2012 at 1:48 AM, algoist <[email protected]> wrote:
>
>> Consider 2 temp arrays, B and C
>>
>> Where B gets updated for every find of 0 and C for every find of 1
>>
>> i.e if(a[i]==0)
>>        b[i]+=b[i-1]+1;
>>        c[i]=c[i-1];
>> i.e if(a[i]==1)
>>        c[i]+=c[i-1]+1;
>>        b[i]=b[i-1];
>>
>> if(c[i]==b[i])
>>   update max.
>>
>> return max.
>>
>> This is O(N) algo. Is it right or i am missing anything here?
>>
>>
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