@zyro May be this solves your problem...............
#include <iostream>
using namespace std;
int main()
{
int no;
char digit[50];
int counter=0;
cin >> no;
do {
if ( no% 2 == 0) {
digit[counter++]='0';
}
else
{
digit[ counter++ ]='1';
}
if ( no < 0 ){
no = (1 - no)/2;
}
else if(no>0){
no = -no/2;
}
}
while ( no );
for ( int i = counter- 1; i >= 0; i--) {
cout << digit[ i ] ;
}
cout << endl;
return 0;
}
On Sun, Jan 29, 2012 at 8:51 PM, saurabh singh <[email protected]> wrote:
> Use a pen and paper....:) Generate a few numbers in base -2 by hand.You
> will get the logic.
> Saurabh Singh
> B.Tech (Computer Science)
> MNNIT
> blog:geekinessthecoolway.blogspot.com
>
>
>
> On Sun, Jan 29, 2012 at 11:44 PM, Zyro <[email protected]> wrote:
>
>> 0
>
>
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--
-Sharad Dixit
B.Tech(IT)
Indian Institute of Information Technology Allahabad
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