http://www.geeksforgeeks.org/archives/4722
O(logn) soln...

Regards,
PAYAL GUPTA,
NIT-B

On Thu, Feb 9, 2012 at 5:33 PM, atul anand <[email protected]> wrote:

> ignore my comment...
>
>
> On Thu, Feb 9, 2012 at 4:15 PM, Ashish Goel <[email protected]> wrote:
>
>> log n is impossible. the other solution i thought was of building a tree
>> where each node contains value and its count. and then building a heap out
>> of these counts, but this will be overkill.
>>
>> the fact that rest of the n/2 elements are not unique is the killer in
>> the logic otherwise only n/2+1 elements are sufficient
>>
>> Best Regards
>> Ashish Goel
>> "Think positive and find fuel in failure"
>> +919985813081
>> +919966006652
>>
>>
>>
>> On Thu, Feb 9, 2012 at 2:53 PM, atul anand <[email protected]>wrote:
>>
>>> i guess can be done using binary indexed tree.
>>>
>>>
>>> On Thu, Feb 9, 2012 at 2:07 PM, Prakhar Jain <[email protected]>wrote:
>>>
>>>> But in this post, we don't have prior information about what can be
>>>> possible majority element.
>>>>
>>>> According to my question, we know that either x is the majority element
>>>> or there is no majority element.
>>>> Can we use that information to reduce complexity to O(log n)..???
>>>>
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