@Gene : Thanx for the reply. Understood your point.

On Tue, Mar 6, 2012 at 6:24 AM, Gene <[email protected]> wrote:

> What Don so succinctly said is this: Comparison sort _requires_ O(n
> log n) comparisons. If you had the data structure you're asking for,
> you could easily implement a comparison sort: Just insert n items,
> then then repeat n times: find min and delete that min.  With your
> proposed time bounds, the resulting sort would be O(n). This is how
> you can immediately tell what you're asking for is impossible.
>
>
> On Mar 5, 5:51 pm, Sehaj Singh Kalra <[email protected]> wrote:
> > Ok. Got it. I think that without the assumption that you took ( about
> FIFO
> > implementation i.e. only the recent most element to be added can be
> deleted
> > or else there would be problem in updating stack 2) the problem can't be
> > done. Thanks for the proposed solution.
> >
> > On Tue, Mar 6, 2012 at 4:13 AM, SAMM <[email protected]> wrote:
> > > As I mentioned we have to use hashing using Separate Chaning to find
> the
> > > element in constant time . This is different than than opening
> addresing
> > > which added the element to the next free slot in case of a collision ,
> so
> > > we cann't  keep track of the element in a constant . In sepate Chaning
> the
> > > elements when collision is found the element will be in the stored in
> the
> > > form of the linked list on the same slot . IN worst case if all the
> element
> > > give collision then  the time complexity can be of O(n) .  But
> chossing the
> > > proper hash key can give the result in constant time .
> >
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