how about going through every truck and doing temp=(free_space - load);
if(temp < min && temp >=0)
{
min=temp;
truck = i;
}
now after traversing we have found the truck where we can add load.
no need of sorting....
complexity =O(n) where n is number of trucks
space complexity = constant
On Sat, Mar 10, 2012 at 10:45 PM, Bhavani Pradeep <[email protected]>wrote:
> and i guess there can be multiple input loads too... i saw the same
> question elsewhere too
>
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