@rahul: i have alreday explained it in the provided link.
@sourbh : why it would not work for large dimension
On 14 Mar 2012 19:39, "rahul sharma" <[email protected]> wrote:

> @atul..plz tell me an example for square matrix...actually i faced it
> first tym...it executes...but explain plz..
>
> On Wed, Mar 14, 2012 at 6:56 PM, Sourabh Singh 
> <[email protected]>wrote:
>
>> @atul
>>
>> Also the histogram algo and algo given by you can't work on very very big
>> dimentions. say 10^5 x 10^5 matrix.
>>  but if we can find a DP then  we just need to keep 2 row's at a time. :-)
>>
>>
>>
>> On Tue, Mar 13, 2012 at 1:03 PM, Sourabh Singh 
>> <[email protected]>wrote:
>>
>>> @atul
>>>
>>> read it ..
>>>
>>> it's good but more or less like the histogram algo.. i wanted a DP.
>>> approach..
>>>
>>> here is some of wat i heard from a senior in colg..
>>>
>>> 1. at every index we can keep 4 variable
>>>
>>> ht: height of max rectangle possible at index above current
>>>  wt width   "   "          "             "             "
>>> "           "
>>>  hl:height of max rectangle possible at index left of  current
>>> wl:   "            "        "               "             "
>>> "            "
>>>
>>>
>>> now problem is which one to take for current... index
>>>
>>>
>>>
>>> On Tue, Mar 13, 2012 at 10:52 AM, atul anand <[email protected]>wrote:
>>>
>>>> @ Sourabh: check solution i have posted in below link
>>>>
>>>>
>>>> http://groups.google.com/group/algogeeks/browse_thread/thread/91a17f7c78c2319e/991d1c2625a62ff0?hl=en&lnk=gst&q=rectangle+of+max+sum+MS+Q#991d1c2625a62ff0
>>>>
>>>>
>>>>
>>>> On Tue, Mar 13, 2012 at 10:26 PM, Sourabh Singh <
>>>> [email protected]> wrote:
>>>>
>>>>> @ ALL
>>>>>
>>>>>  finding square matrix is quite a standard question and nw an easy one
>>>>> as everyone knows the reccussence atul has given.
>>>>>  but  i wanted to find max rectangle..
>>>>>
>>>>> i know there is a DP for it. in O(n^2). for nxn matrix..don't know the
>>>>> whole approach .but  here is what i remember..
>>>>>
>>>>> 1. aproach is simple to keep track of max rectangle which can be
>>>>> formed from any point taking that point as top  left corner of max
>>>>> rectangle and
>>>>>     proceed further down .
>>>>>
>>>>> can someone suggest how can be proceed further..
>>>>>
>>>>>
>>>>> [ NOTE: problem occurs mainly when their are more than one rectangles
>>>>> which can be formed from same point ]
>>>>>
>>>>> plz.. don't suggest the histogram method it's just a dirty way of
>>>>> avoiding to work on getting this DP right. :-)
>>>>>
>>>>>
>>>>> On Mon, Mar 12, 2012 at 11:29 PM, atul anand 
>>>>> <[email protected]>wrote:
>>>>>
>>>>>> here is the recurrence for solving this
>>>>>>
>>>>>> R[i, j] = (M[i,j] == 0 ? 0 : 1 + min( R[i-1, j], R[i-1, j-1],
>>>>>> R[i,,j-1] ) );
>>>>>>
>>>>>>
>>>>>> On Tue, Mar 13, 2012 at 11:48 AM, rahul sharma <
>>>>>> [email protected]> wrote:
>>>>>>
>>>>>>>
>>>>>>>  April 4, 2010
>>>>>>>
>>>>>>> Given a binary matrix, find out the maximum size square sub-matrix
>>>>>>> with all 1s.
>>>>>>>
>>>>>>> For example, consider the below binary matrix.
>>>>>>>
>>>>>>>    0  1  1  0  1
>>>>>>>    1  1  0  1  0
>>>>>>>    0  1  1  1  0
>>>>>>>    1  1  1  1  0
>>>>>>>    1  1  1  1  1
>>>>>>>    0  0  0  0  0
>>>>>>>
>>>>>>> The maximum square sub-matrix with all set bits is
>>>>>>>
>>>>>>>     1  1  1
>>>>>>>     1  1  1
>>>>>>>     1  1  1
>>>>>>>
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